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Teenager Moody Knocks Out Four-Time Champion Higgins at British Open

Nineteen-year-old Stan Moody secured a 4-2 victory over four-time champion John Higgins in the last-16 of the British Open.

  • Stan Moody, 19, defeated John Higgins 4-2 in the British Open last-16.
  • Moody will now face Liam Highfield in the quarter-finals.
  • Judd Trump, Jack Lisowski, Mark Selby, Jak Jones, Aaron Hill, and Liam Highfield also progressed.

Teenage snooker sensation Stan Moody has delivered a significant upset at the British Open, knocking out four-time champion John Higgins with a 4-2 victory in the last-16. The 19-year-old's impressive performance in Cheltenham sees him advance to the quarter-finals for the second consecutive year.

Halifax-born Moody established leads of 1-0 and 2-1, with Higgins, 51, levelling the score on both occasions. Moody then pulled ahead 3-2 with a break of 46, before sealing the win in the sixth frame with a clearance of 69, despite Scottish veteran Higgins initially leading 61-0.

Moody is now set to face fellow Englishman Liam Highfield in the quarter-finals. Other players who have progressed include Judd Trump, who swept past David Gilbert 4-0, and Cheltenham's Jack Lisowski, who triumphed 4-1 over Lyu Haotian and will play Mark Selby on Friday.

Why this matters: The victory marks a notable achievement for the young player, progressing to the quarter-finals for the second year running.

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